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Comments (4)

taifu avatar taifu commented on September 18, 2024 1

My workaround is ugly, I call this function in my main:

def check_windows_exe(app_name):
    import platform
    if platform.system() == "Windows":
        to_file = os.path.join(__file__, app_name)
        from_file = to_file + ".exe"
        if os.path.exists(from_file) and not os.path.exists(to_file):
            import shutil
            shutil.copyfile(from_file, to_file)

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taifu avatar taifu commented on September 18, 2024

Same error here: did you fixed it somehow? Ty.

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arthursw avatar arthursw commented on September 18, 2024

I have the same problem and found a workaround.

Since the problem occurs only on Windows when called from the command line shortcut (commandName or commandName.exe); and not from the python file (python path/to/commandName.py works fine), I call the actual python script when I am in this case.

At the beginning of commandName.py:

import sys, platform, subprocess

if platform.system() == 'Windows' and not sys.argv[0].endswith('.py'):
        subprocess.call([sys.executable, __file__])
        sys.exit()
        
# [...] rest of the script

sys.argv[0] is the name of the calling command, it should end with .py otherwise the command python __file__ is run. __file__ is the current file path (of commandName.py) and sys.executable is the python executable.

In my case I only open the gui when there are no arguments (when len(sys.argv) == 1) so I do not need to pass them to the subprocess, but it should be possible with subprocess.call([sys.executable, __file__] + sys.argv[1:]).

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arthursw avatar arthursw commented on September 18, 2024

This workaround might not work for a PyInstaller or cs_Freeze app, since sys.executable will not point to a python interpreter.
Well actually I just test it, I don't have the problem with PyInstaller (and probably neither cs_Freeze) since it does not make use of the console script!

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