Unable to run example asyncio code about rubicon-objc HOT 4 CLOSED

As always debugging asyncio code is a bit of a PITA :-)

I can point you at a working example using Rubicon's CocoaLifecycle - toga. The cocoa and iOS backends both use Rubicon.

You may also have some luck looking at the unit tests for the asyncio code

As for debugging what is going on in this case - I tried copy/pasting that code to my own machine, and ran it (Mojave 10.14.2, Python 3.7), and it worked. It didn't do anything - but then, it's just starting an application, so there won't be anything visible happening. Can you share any more details about your testing environment?

from rubicon-objc.

Thank you for the links to working examples, and thank you for confirming that it works on your machine. I'm also running Mojave 10.14.2, Python 3.7, but I realized something else; I only get the error on subsequent program runs. I can run it, then exit (via Quit on the rocket ship icon), then run it again, and immediately get the error. If I wait some amount of time, a few minutes perhaps, it will run again without error. That seems undesirable, but it may be a result of how I'm killing the application...?

from rubicon-objc.

That behavior suggests the problem is a socket resource not being released.

You say you are getting the rocket ship icon and using Quit from the application menu - I take it this means you're using a python.org installer version of Python? In that case, it's possible that what you're quitting by using the menu is Python, not the NSApplication - and as a result, the network resources consumed by the event loop may not be released correctly. I'm not sure if that's a problem with Python or Rubicon, though...

For the record - I'm using a pyenv installed version, so I don't get the rocket ship. I'm staring the app from the command line, and terminating the program using CTRL-C. If you do the same, what behavior do you see?

from rubicon-objc.

I'm unsure how it was installed, as Python came pre-installed (I'm using MacInCloud). I am also starting the app from the command line, but this example program will not exit via CTRL-C. Oddly enough, I am able to exit other Python programs with CTRL-C.

As my error appears to be related to how I'm exiting Python, I'll go ahead and close this issue. Thanks again for your responses and the hint to read through the toga implementation!

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