Comments (12)
在从药瓶里倒出1粒药片A,现在有4片药,把每片药都切一半,然后只吃每片药的一半,剩下的4分半片药第二天吃
from leetcode.
哈哈,可以拿出一个A在弄成粉末,分成2次就可以了
from leetcode.
再倒出一片A在0点服下4颗药? 跑了 跑了。。
from leetcode.
在不破坏药片、或借助量器的情况下,无解
from leetcode.
在不破坏药片、或借助量器的情况下,无解
那如果可以破坏呢
from leetcode.
This issue has been automatically marked as stale because it has not had recent activity. It will be closed if no further activity occurs. Thank you for your contributions.
from leetcode.
I'm assuming that pills A and B taste differently. So take half of each, that way you will know which tastes different, and then u can half the other half from differently tasting pill. Thus you will have exact amount of dose.
from leetcode.
from leetcode.
from leetcode.
from leetcode.
I'm assuming that pills A and B taste differently. So take half of each, that way you will know which tastes different, and then u can half the other half from differently tasting pill. Thus you will have exact amount of dose.
pill A and pill B may have same taste. I will post my anwser below in both English and Chinese
from leetcode.
我们可以将手中的三个药片均进行二等分,然后将其中一半放到左面,另一半放到右面。这样下来,左面和右面分别有半个A和一个B。接下来,我们再从A中拿出一片药,同样进行等分操作,即进行二等分,然后将其中一半放到左面,另一半放到右面。
这样左右两面都有一个A和一个B,吃其中一组,第二天吃剩下的一组即可。
We can divide the three pills in our hand into two parts, and then put half of them on the left side and the other half on the right side. In this way, there are half A and one B on the left and right respectively. Next, we take out a piece of pill from A, and perform the same division operation, that is, divide it into two equal parts, and then put half of it on the left side and the other half on the right side.
In this way, there is an A and a B on the left and right sides, eat one of them, and eat the rest the next day.
from leetcode.
Related Issues (20)
- 算法学习 HOT 1
- 树专题中双色标记法后序和前序写反了 HOT 2
- leetcode/thinkings/tree.md 出错 HOT 1
- some error
- 二分查找专题,寻找最左/右插入位置算法模板错误问题 HOT 9
- possible code error in thinkings/heap.md HOT 1
- link error HOT 4
- link is not correct
- [695.最大岛屿面积,360,面试原题]【每日一题】 HOT 3
- 【专题】 反向思考 HOT 3
- 【专题】 考虑每一项对结果到的贡献
- 【专题】递推方程时间复杂度优化
- 已发布文章的代码错误 HOT 7
- Remove duplicate CPP solution and add Python solution for problem 100.same-tree
- Add OSSF Scorecard security workflow
- 题目的排版可否改一改
- 关于二分法中查找中间点索引的算式 HOT 6
- leetcode-thinkings-tree.md BFS 模版调整 HOT 3
- anki-card 中只有10道题吗?截止到2023.11 HOT 1
- 【每日一题】- 2020-xx-xx - xxx
Recommend Projects
-
React
A declarative, efficient, and flexible JavaScript library for building user interfaces.
-
Vue.js
🖖 Vue.js is a progressive, incrementally-adoptable JavaScript framework for building UI on the web.
-
Typescript
TypeScript is a superset of JavaScript that compiles to clean JavaScript output.
-
TensorFlow
An Open Source Machine Learning Framework for Everyone
-
Django
The Web framework for perfectionists with deadlines.
-
Laravel
A PHP framework for web artisans
-
D3
Bring data to life with SVG, Canvas and HTML. 📊📈🎉
-
Recommend Topics
-
javascript
JavaScript (JS) is a lightweight interpreted programming language with first-class functions.
-
web
Some thing interesting about web. New door for the world.
-
server
A server is a program made to process requests and deliver data to clients.
-
Machine learning
Machine learning is a way of modeling and interpreting data that allows a piece of software to respond intelligently.
-
Visualization
Some thing interesting about visualization, use data art
-
Game
Some thing interesting about game, make everyone happy.
Recommend Org
-
Facebook
We are working to build community through open source technology. NB: members must have two-factor auth.
-
Microsoft
Open source projects and samples from Microsoft.
-
Google
Google ❤️ Open Source for everyone.
-
Alibaba
Alibaba Open Source for everyone
-
D3
Data-Driven Documents codes.
-
Tencent
China tencent open source team.
from leetcode.