Invalid argument(s): No encoder to encode the value about dart-xmlrpc HOT 4 CLOSED

No problem, got it! The authenticate url should also use '/xmlrpc/2/common', it wasn't obvious in the doc. And <String, dynamic>{} did the trick 👍

Thanks again for your help!

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I'm not sure if the error comes from request or response as I can't test it.

The standard codecs support Map<String, dynamic> but not other maps so you perhaps have to use ['db-odoo', 'firstname.name', 'my-pwd', <String, dynamic>{}] instead of ['db-odoo', 'firstname.name', 'my-pwd', {}].

Moreover you can use async/await to make the code easier to read.

  try {
    final versionResult =
        await xml_rpc.call(url + '/xmlrpc/2/common', 'version', []);
    print(versionResult);
    final authenticateResult = await xml_rpc
        .call(url, 'authenticate', ['db-odoo', 'firstname.name', 'my-pwd', <String, dynamic>{}]);
    print(authenticateResult);
  } catch (error) {
    print(error);
  }

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Hi @a14n thanks for the answer. Unfortunately moving to <String, dynamic>{} gave me an error 400 bad request.

If you provide me your mail, I can give you some credential. Thanks again!

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If you now get a 400 it means that the request is well encoded and sent to the server. It seems to be an issue with the API usage of the remote service.

Sorry but I don't have the time to read the doc and try to make it works :-/

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